Keith's Weblog: Comments on "Updated function to merge two PHP arrays"

by M. Bean

Fri, 11 Jul 2003 05:04:22 +0000

hehe... I was reading that as "a to the power of b", in which case I was like "what kind of crack are you smoking?"

by Adam Langley

Fri, 11 Jul 2003 10:16:45 +0000

Well, http://www.imperialviolet.org/page10.html#e182 suggests that ∩ would do the trick. I'm not sure if you escape ampersands, so that's amp-cap-semicolon if you dont

AGL

by Keith

Fri, 11 Jul 2003 13:36:14 +0000

Neat! Actually, HTML is escaped automatically, so I don't think I could do that if I wanted to Something to think about for the next version of my parser though.

by M. Bean

Fri, 11 Jul 2003 15:37:01 +0000

Well, let's find out... ∩ is unescaped... and escaped, here it comes... wooo.... my heart is beating so quickly, I can't stand it! \∩ Did it work?

by M. Bean

Fri, 11 Jul 2003 15:37:14 +0000

Oh, no! DENIED.

by Keith

Fri, 11 Jul 2003 18:38:11 +0000

Told you!

by Michael

Wed, 20 May 2009 07:04:43 +0000

I realise this is a very old post, but just to let you know that there is a problem with the last merge function.

$arr1[0] = 15;
$arr1[2] = 30;

$arr2[1] = 45;
$arr2[3] = 60;

merge ($arr1, $arr2);

var_dump ($arr1);

Will delete all the values in $arr1 and replace them with $arr2 due to "!array_key_exists(0, $a)" in the first "if" statement.

by Keith

Wed, 20 May 2009 21:18:01 +0000

Will delete all the values in $arr1 and replace them with $arr2 due to "!array_key_exists(0, $a)" in the first "if" statement.

Working as intended. It's meant to merge associative arrays, not normal arrays, and that's what the check is there for. Yes it's a kludge cause there's no sure way to know whether a PHP array is intended as an associative array or as a normal array.